1/2r^2=3/2r^2-5/2r

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Solution for 1/2r^2=3/2r^2-5/2r equation: 


r in (-oo:+oo)

(1/2)*r^2 = (3/2)*r^2-((5/2)*r) // - (3/2)*r^2-((5/2)*r)

(1/2)*r^2-((3/2)*r^2)+(5/2)*r = 0

(1/2)*r^2+(-3/2)*r^2+(5/2)*r = 0

5/2*r-r^2 = 0

DELTA = (5/2)^2-(-1*0*4)

DELTA = 25/4

DELTA > 0

r = ((25/4)^(1/2)-5/2)/(-1*2) or r = (-(25/4)^(1/2)-5/2)/(-1*2)

r = 0 or r = 5/2

r in { 0, 5/2 }

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